Question

[tommylorna]

Can anyone tell me the following, how do you change a horses beaten lengths into time.
Say a horse lost 2.5 lengths, to the winner who won in 60secs, how do I adjust that time for the lengths btn.
Do I just add the lths to the 60 making the horse btn time 62.5, or do I times the 2.5 by .2. Making the btn horse with a time of 60.50.
What I really want to know is how to change lths into secs.

[apracing]

Here’s the official version in full detail:

http://www.britishhorseracing.com/resou … second.asp

[homersimpson]

Well lets work this out. 5 furlong race run in 60 seconds. 1 furlong = 660 feet. Therefore 5 furlongs =

3,300 feet

Length of 1 horse = 8 feet

Therefore 5 furlongs = 412.5 horse lengths.

Therefore LpS = 412.5 divide by 60

= 6.88.

Not exactly sure if this is an average 5 furlong time but it must be there or thereabouts for a Good surface.

In summary

Seems reasonable to me

[TheBluesBrother]

.2 = 1 length

60s + (2.5 x .2) =

60.5s

[Gladiateur]

Why doesn’t the BHA abolish giving official "distances" in lengths and just give time differences instead?

[tommylorna]

Thanks guys
Hommer can you tell me where do you get the lth of horse being 8ft from.

[homersimpson]

Thanks guys
Hommer can you tell me where do you get the lth of horse being 8ft from.

http://en.wikipedia.org/wiki/Horse_length

[homersimpson]

Thanks guys
Hommer can you tell me where do you get the lth of horse being 8ft from.

To what nth of a second Eg. how many nths of a second is a "Snotty Nose"

[TheBluesBrother]

Thanks guys
Hommer can you tell me where do you get the lth of horse being 8ft from.

http://en.wikipedia.org/wiki/Horse_length

Using the BHA scale:
length of a horse = 10ft
1 length = 0.2s

******************************
To calculate a length using a horse length as 8ft.

5f race winners time was 60.0s.

(5f X 660ft) / 8ft = 412.5 lengths

Divide the winners Time (60.0s) by the lengths

60 / 412.5 = 0.145 (0.15)

So 1 length in this race =

0.15s

(The BHA use

0.2s

as a constant)

So if you use 10ft as the length of a horse, 1 length would have been

0.18s

So the time for a horse beaten 2.5 lengths becomes
60+(2.5 x .18) =

60.45s

Easy isn’t it

[Blue1878]

Isn’t this whole concept based on the Timeform model ? and after many years of subscribing (losing) I prefer my eye looking at the horse’s form, jockey and the ground.

[venje]

Winning time 60
Distance 5 fur = 3300 Ft (660 ft in a furlong)
Distance btn =2.5

Depending on what books you read the average length of a horse is either 8ft or 10ft

therefore 2.5 lengths * 8 = 20ft

3300-20=3280

divide 3280 by winning time 60 = 54.67

divide 3300 by 54.67 = 60.36secs

As blues brother said easy isn’t it:)

John

[Author]

Posts