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Losing Streak

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  • #1277250
    Avatar photoDrone
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    • Total Posts 6156

    There’s a typo in your first list: it should read If 40% SR a 10 losing run in 413

    I needed the chicken before the egg, as without the numbers I wouldn’t have been able to find the equation! Though having now found it I do recall having known it in the dim and distant. A genuine thanks for giving me the opportunity to refresh my memory Gingerdecimals

    The formula for calculating the number of bets at a strike-rate SR over which of a losing run of length LR would be expected to occur is:

    (100/100-SR)^LR x 100/SR

    e.g.

    for an LR of 10 and SR of 50%:
    (100/100-50)^10 x 100/50
    (100/50)^10 x 2
    = 2^10 x 2
    = 1024 x 2
    =2048

    an LR of 10 and SR of 30%:
    (100/100-30)^10 x 100/30
    (100/70)^10 x 3.33
    1.429^10 x 3.33
    = 118

    an LR of 20 at SR 20%
    (100/100-20)^20 x 100/20
    (100/80)^20 x 5
    = 1.25^20 x 5
    = 86.736 x 5
    = 434

    note that LRs at 50% SR are simply 2 raised to the power of LR+1
    e.g. LR10 at SR50 = 2^11 = 2048

    Of course, none of this means the calculated losing runs will happen, just that they can be expected to happen: that’s Probability/Possibility for you :wacko:

    #1277256
    Avatar photoGingertipster
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    • Total Posts 34708

    There’s a typo in your first list: it should read If 40% SR a 10 losing run in 413

    :good:

    Value Is Everything
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