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carlisle.
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- June 4, 2007 at 10:41 #1881
I know this has been raised on here before, and from what I remember without a satisfactory conclusion, but has anybody got any ideas on how to calculate place odds based on win odds.
I tend to just divide the win odds by the number of places available e.g. A horse at 9/1 in an 8 runner hcap would have place odds of 3/1?
But this is a bit crude and doesn’t take into account the shape of the book such as when a very shortpriced fav is distorting the odds.
So has anybody got any better suggestions?<br>
June 4, 2007 at 11:45 #63692Alan,
Do you mean forecasting your own or working out what they are? Because if its the latter you would just multiply it by the fraction that the bookies are offering for places i.e. 1/5th or 1/4 on 16 runner handicaps..
There are other people on here much better informed on the former.
June 4, 2007 at 13:38 #63693I’m trying to work out the REAL odds. So in a 100% book what are the real odds of a horse being placed.
I’m not trying to calculate what a bookmaker would pay out.
June 4, 2007 at 15:33 #63694
AnonymousInactive- Total Posts 17716
Quote: from alan1 on 2:38 pm on June 4, 2007[br]I’m trying to work out the REAL odds. So in a 100% book what are the real odds of a horse being placed.
I’m not trying to calculate what a bookmaker would pay out.
Alan<br>I’m no statistician, but surely for 3 places you would multiply the 2nd part of the sp by 3, for 4 places by 4 etc., so that 4/1 against a win equates to 4/3 for a place, and so on?<br>       ÂÂÂ
June 4, 2007 at 15:54 #63695You can’t calculate real place odds from real win odds.
June 4, 2007 at 16:05 #63696
AnonymousInactive- Total Posts 17716
Quote: from dave jay on 4:54 pm on June 4, 2007[br]You can’t calculate real place odds from real win odds.
Errmm,………Alan did state ‘a 100% book’.<br>8 rnrs @ say: 7/1 the field = 7/3 the place, unless I’m missing something?<br>
June 4, 2007 at 16:12 #63697Try googling "Harville Formula" and the -s -e plurals, and maybe adding "Benter" to narrow it down<br>
(Edited by Drone at 5:12 pm on June 4, 2007)
June 4, 2007 at 16:30 #63698You could use the Harville formula or simply multiply your win odds by the number of places, but it doesn’t work because a horse that hasn’t got a chance of winning might have a very good chance of placing, and visa-versa, as I suspect you are finding out Alan. You are better off trying to work out what you think the place odds actually should be rather than trying to work them out from the win odds, IMO.
June 4, 2007 at 16:56 #63699Very difficult to do, and almost impossible to do accurately.
Basically, the shape of the market is all important.
A 7/1 shot in one 8-runner race where all the runners have an equal chance of winning doesn’t have the same chance of placing as a 7/1 shot in another 8-runner race where there is an odds-on favourite.
In essence, you have to build a model which uses a 100% book to calculate the chances of each horse coming second to each other horse, and then onwards if there are 3 or 4 places.
I have just thrown together something for 5-runner races which is of limited use but does illustrate the point. Realistically, this could be expanded to 6-runners without becoming unwieldly, but unless you are happy to bung ‘the field’ in as one selection, probably won’t be of much practical use…
June 4, 2007 at 17:37 #63700I agree with dave jay.
You can use a mathematical model to provide you with a starting point but the individual horses and even the races they are running in count for a great deal.
June 4, 2007 at 18:31 #63701
AnonymousInactive- Total Posts 17716
<br>Surely, if you use a mathematical model based on win odds a 1/5 shot is 1/15 to place, and anything that can’t be proven mathematically becomes subjective, and therefore as open to individual interpretation as any theoretical book, win or place?
June 4, 2007 at 18:45 #63702Depending on the shape of an 8-runner race, a 5/1 shot in the win market can range from 1.3 to 2.5 in the place market (if not greater variance).
How does the mathematical model based on win odds help here?
June 4, 2007 at 18:48 #63703The mathematical model is, I believe, Harville’s, as mentioned before and as used (but not credited) in The Mathematics of Betting by Phil Bull. The mathematically "true" odds are arrived at by a much more complex process than simple division.
However, that can only ever be a starting point. There are limiting factors on how close to "certainty" a horse’s place odds can get. ÂÂÂ
Would you back an even-money shot in a 15-runner novice chase at 1/5 to be placed, given that if it does not win it could well have fallen, unseated, been brought down or carried out?
Then there are the horses themselves. I’m sure we can all quote examples of horses who are good at being placed but seldom win; of horses (or should that be trainers?!) who either win or are not sighted; and of horses whose running style lends them to all or nothing or the opposite.
(Edited by Prufrock at 7:54 pm on June 4, 2007)
June 4, 2007 at 19:03 #63704I haven’t come across this debate before so I’m thinking as I go, therfore my thinking will probably be flawed…
A 7/1 chance means the horse as one chance in 8. To be placed therefore means 3 chances in 8, or 5/3. It’s a huge difference and probably explains why place-only odds against the first five or six in the market often appear very skinny.
If I can get 1/4 or 1/5 the win odds, I reckon I’m doing very well. If you fancy an 8/1 shot EW at 1/4 the odds, your £1 EW (outlay £2) nets you £12 (ie 5/1 overall). If it only gets placed, your returns are £3 (ie 1/2 overall). If you are unsure about the horse winning, I reckon you’re a lot better trying to get 2/1 place-only for a £6 return, but you’ll probably struggle to get it.
June 4, 2007 at 19:15 #63705Just reading round the subject on t’internet and the fact that the purely mathematical principles of Harville’s Probabilities do not accurately reflect "real life" seems to have been addressed by something called "Discounted Harville’s".
Anyone who has played place markets at all frequently will know just what a complex subject this is to pin down.
June 4, 2007 at 20:07 #63706The Harville formula is more suited to pool betting, where there is a more or less fixed favourite/long shot bias on the win market, imo.
There are better ways of calculating place odds and it won’t be a linear equation.
Needless to say, anyone who cracks the code would very wealthy in a short space of time, the same as those that can say what price a horse should be to win.
June 4, 2007 at 21:14 #63707Another issue is that even with a discounted average Harville of some 70%, UK prize money for placing 2,3,4 is so poor that it is hardly worth trying for unless in with a good chance of winning at the finish, and for handicaps, placing can further penalise the horse with a future weight rise.
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